forEach方法

void forEach(
  1. void f(
    1. E element
    )
)

在此可迭代对象的每个元素上迭代顺序调用action

示例

final numbers = <int>[1, 2, 6, 7];
numbers.forEach(print);
// 1
// 2
// 6
// 7

实现

void forEach(void f(E element)) {
  int modificationCount = _modificationCount;
  for (int i = _head; i != _tail; i = (i + 1) & (_table.length - 1)) {
    f(_table[i] as E);
    _checkModification(modificationCount);
  }
}