SplayTreeMap<K, V>.of 构造函数

SplayTreeMap<K, V>.of(
  1. Map<K, V> other,
  2. [int compare(
    1. K key1,
    2. K key2
    )?,
  3. bool isValidKey(
    1. dynamic potentialKey
    )?]
)

创建一个包含所有键值对的 SplayTreeMap，例如。实现

final baseMap = <int, String>{3: 'A', 2: 'B', 1: 'C', 4: 'D'};
final mapOf = SplayTreeMap<num, Object>.of(baseMap);
print(mapOf); // {1: C, 2: B, 3: A, 4: D}

实现

factory SplayTreeMap.of(Map<K, V> other,
        [int Function(K key1, K key2)? compare,
        bool Function(dynamic potentialKey)? isValidKey]) =>
    SplayTreeMap<K, V>(compare, isValidKey)..addAll(other);